An organic compound ‘A’ with molecular formula C6H7N, on treatment with NaNO2 + HCl at 273 − 278 K, gives an intermediate ‘B’ that reacts with cuprous chloride to form ‘C’. Compound ‘C’ reacts with methyl chloride in the presence of anhydrous AlCl3 to form ‘D’ and ‘E’. Among ‘D’ and ‘E’ the major product on treatment with sodium in dry ether forms compound ‘F’. Identify compounds A to F. Write the reactions involved.
OR
Complete the given reactions.
a.
b.
c.