Genius Jnr - The bisects of exterior angle at B and C of ΔABC meet at O. If &ang;A = x°, then &ang;BOC = (a) 90°+x°2 (b) 90°-x°2 (c) 180°+x°2 (d) 180°-x°2

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The bisects of exterior angle at B and C of ΔABC meet at O. If ∠A = x°, then ∠BOC =

(a)

90 ° + \frac{x °}{2}

(b)

90 ° - \frac{x °}{2}

(c)

180 ° + \frac{x °}{2}

(d)

180 ° - \frac{x °}{2}

i	ii
copper oxide	copper carbonate

i	ii
copper oxide	copper hydrogen carbonate

i	ii
copper hydroxide	copper carbonate

i	ii
copper hydroxide	copper hydrogen carbonate

or

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